Based on the followings process steps can you determine the final…

Based on the followings process steps can you determine the final composition of the filtrate solution that goes into the F-511 as well as the composition of the yellow oil in V-113 steps 13-14 :
can you write out a complete chemical formula balanced equation .

Solution preparation
1. In T-101, Guaiacol dissolved in ethanol was prepared with a concentration of 1.667 mol/L ethanol.
2. In T-102, mixture of NaOH and water (25% excess#) was prepared with a concentration of 6.25 mol/L water.

Reaction
3. Both solutions from T-101 and T-102 were transferred to V-111 and mixed thoroughly. Afterwards, a premix (1:1 volume ratio) of 3-chloropropane-1,2-diol in ethanol (19.6% excess#) was charged through IS-200 via a transfer pump (P-101). (Sr. no. 2.10) *To fill the pipes, and account for losses during the setup and transfer, a 10% additional volume of 3-chloropropane-1, 2-diol: Ethanol (1:1) -premix was prepared (in Bill of raw materials)
4. In V-111, synthesis was completed after reflux at 80oC for 1 hr. (Sr. no. 2.12)
5. After synthesis, the API (Guaifenesin) was formed. The mass of the API strongly depends on the conversion of the reaction, which was reported as the yield %. (Sr. no. 2.13) Yield % = Actual API mass obtained / expected API mass *100 % * Expected mass is the mass at 100% yield (no loss)
6. Additional workup steps were carried out in V-111, V-112 and V-113 before the final filtration (F-511) and drying (D-511).

Work-ups (V-111)
7. In V-111, 90% (volume basis) ethanol was removed via vacuum evaporation. (Sr. no. 3.3) 8. Water was added to dissolve the NaCl. The volume of water added (Vwater) was calculated based on the solubility at 80oC, with 29.2% (by mass) excess. (Sr. no. 3.5) *Solubility of NaCl in water @ 80oC = 40 g NaCl / 100g Water
9. Next, liquid-liquid extraction (LLE) was carried out to remove the aqueous layer. *LLE is a separation process where compounds were separated based on their relative solubilities in two different immiscible liquids usually water (polar) and an organic solvent (non-polar). In this process, the API (Guaifenesin) will dissolve in the organic phase (ethyl acetate) while the aqueous phase consists of NaCl in water. After LLE, the aqueous phase will be discarded.
10. In the first LLE, volume of ethyl acetate (Vethyl acetate = 10 × Vwater) was added to extract the aqueous layer (NaCl in water). The organic layer was collected in V-112, and the aqueous layer will be drained to the waste reservoir (R-543). The drained content consists of 95% of the total volume of aqueous layer and 0.8% (by volume) of Vethyl acetate. (Sr. no. 4.1 & 4.6 – 4.7)
11. In the second LLE, the same volume of ethyl acetate added during the first LLE was added. The organic layer was collected in V-112, and the aqueous layer was drained to the waste reservoir (R-543). The drained content consists of all of the remaining aqueous layer and 0.3% of total volume of ethyl acetate. (Sr. no. 4.10 & 4.15)

Work-ups (V-112)
12. Water in the organic layer in V-112 was dried by absorption using MgSO4. After drying, all the MgSO4 (together with the absorbed trace water) are removed via in-line filtration (F-112, F113). (Sr. no. 5.5 & 6.0) *Amount of MgSO4 is 5% of the weight of ethyl acetate in the organic layer (in V-112) * Bulk of the water was removed by LLE. However, the process yield is highly sensitive to the presence of trace water. Therefore, MgSO4 was used to remove trace water in the organic layer. This trace water will be absorbed by MgSO4. MgSO4 is a solid, and it will be retained in the in-line filter (F-112, F-113) after filtration.

Work-ups (V-113)
13. The filtrate will be collected in V-113 for vacuum distillation (to remove ethyl acetate and ethanol completely). After distillation, a yellow oil (batch size) consisting of the crude API will remains in V-113, while the solvent (ethyl acetate, ethanol) will be drained to R-543. (Sr. no. 6.6 – 6.7) 14. Volume of hexane (Vhexane) was added to solidify the crude oil in the yellow oil as solid. The mass of hexane added will be 10× the mass of the yellow oil obtained. (Sr. no. 6.11) *Solubility of Guaifenesin in Hexane @ 5oC = 0.005 kg Guaifenesin / L Hexane *To fill the pipes, and account for losses during the setup and transfer, a 10% additional volume of hexane was prepared (in Bill of raw materials)

Filtration (F-511)
15. Filtration is a solid liquid separation process, where the wet cake was retained on the mesh, while the liquid (filtrate) was collected at R-543.
16. During the process, 90% Vhexane was removed, leaving 10% Vhexane in the wet solid. (Sr. no. 7.5)

Drying (D-511)
17. The wet cake was transferred to the dryer.
18. Drying will progress until the residual moisture content is < 4 wt.%. (Sr. no. 7.14) 19. Once dried, the API: Guaifenesin, will be isolated and packaged. THANKS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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